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Nexperia PMBT2222 NPN switching transistor 10 Characteristics Table 7 Characteristics Symbol Parameter Conditions Min Typ Max Unit ICBO collectorbase cutoff VCB = 50 V;S1 6ë µ S1 S6Û \ ^ * b1 6ë c N N \ K Z v ¥6ä \ K º b v ¥ r \ M ^ > %Ê ¢ b v ¥ _43 l K Z µ S1 S6Û \ K Z1 u G \ v 6This cumulative update has multiple hotfix packages Select and download one of the following packages depending on the country version of your Microsoft Dynamics NAV 16 database Country Hotfix package AT Austria Download the CU 57 NAV 16 AT package AU Australia Download the CU 57 NAV 16 AU package

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= 110°C 1 A P G(AV) Average gate power dissipation T J = 110°C 02 W T stg Storage temperature range Lx01Ey 65 to 150 °C LxNy 40 to 125 T J Operating junction temperature range Lx01Ey 65 to 110 °C LxNy 40 to 110 Note x = voltage, y = sensitivity oHS Compliant R G lass passivated junctions V oltage capability up to 600 V S urgeIG = 2 x IGT, tr ≤ 100 ns F = 1 Hz Tj = 150 °C 50 A/µs VDSM/VRSM Non repetitive surge peak offstate voltage tp = 10 ms Tj = 25 °C VDRM/VRRM 100 V IGM Peak gate current tp = µs Tj = 150 °C 4 A PG(AV) Average gate power dissipation Tj = 150 °C 1 W Tstg Tj Storage junction temperature range Operating junction temperature range 40, PEAK TRANSIENT POWER (w) VDD = 400 V 100 0001 01 R JC = 030°C/W VDS, DRAIN−TO−SOURCE VOLTAGE (V) CAPACITANCE (pF) 1 10 100 1K 100K 01 1 800 40 75 1K Single Pulse TJ = Max Rated R JC = 03°C/W TC = 25°C 10 s 100 ms 1 ms 10 15 100 80 50 175 VDD = 800 V VDD = 600 V f = 1 MHz VGS = 0 V 001 01 1 TJ = 150°C TJ = 25°C

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Therefore, the straintime behavior would be as Figure 155c (b) Crosslinked polystyrene at 150°C behaves as a viscoelastic material (Figure 158, curve B);"0/ 10 !2 3"4 50 "4262 7# %('8 ! = C/(r g) Note This formula requires r > g 8 Example • Your next year's cash flow or parental stipend will be $10,000 Your parents have generously agreed to increase the yearly amount to account for increases in cost of living as indexed by the rate of inflation

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(b) C = Consumption function = 075(Y – T) T = 02Y G = Government Spending = 50 I = Investment Spending = X = M 10 Y = C I G X – M in equilibrium Y = 075(Y – 02Y) 50 10 = 100 075(08Y) Y = 100 06Y 04Y = 100 Y = 250 (c) S = Savings function w/ respect to output = 100 02Y T = Net Taxes = 50 GVDS drainsource voltage 25 °C ≤ Tj ≤ 175 °C 50 V ID drain current VGS = 10 V;Supertex inc does not recommend the use of its products in life support applications, and will not knowingly sell them for use in such appl ications unless it receives an adequate "product liability indemnification insurance agreement" Supertex inc does not assume responsibility for use of devices described, and limits its liabilit y to the replacement of the devices determined

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Example 4 Highpass RL filter A highpass RL filter can be represented by the circuit in the figure below, with r being the internal resistance of the inductor (a) Find V, the ratio of the maximum output voltage V to the maximum input voltage V out,0 /Vin,0 in,0 out,0 (b) Let r =0 Ω, R=50 Ω, and L=250 mHWhat is the frequency if ,0,0Fig 1 375 W Tj junction temperature 55 175 °C Static characteristicsX%w/v = 250 g NaCl/100 mL of solution X = 250% Therefore, a solution with 250 g of NaCl dissolved into 100 mL of water has a %w/v concentration of 250% How many grams of NaOH would be needed to make a 40%w/v solution using deionized water as the solvent?

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